- Tue Jun 19, 2007 5:48 pm
#233622
You can have a "dark side" of a bump, but that bump wil not throw a shadow on another part of the same surface unless its physicaly modeled.simmsimaging wrote: But doesn't that suggest that the bump effect is capable of accounting for it's own shape for direct light, but not indirect light? In other words: it self-shadows and reflects properly for emitters, but not the reflected light off the floor, or the actual reflection of the floor?
That can't be right, can it? Am I missing something obvious? (wouldn't be the first time....)
b